Answer to Question #172392 in Classical Mechanics for Jethro Torio

Question

An object accelerates at point O. At a point 5m from point O the object hits a velocity of 3m/s^-1 if the acceleration is 4m/s^-2

Find the object's position and velocity at t = 2s.

Determine the object's position when velocity is 5m/s^-1

Answer 1

Answer

Velocity of object at t=2 s

$v=4\times 2=8m/s$

Position

$x=8\times 2=16m$

By equation of motion

$v^2=u^2+2as$

Initially u=3m/s

So Displacement

$s=\frac{5^2-3^2}{2\times 4}=2m$

Position at this point x=5+2=7m