Question

A solid rectangular block measures 0.1m by 0.08m by 0.06m and floats freely in a liquid of density 13546kg/m3. If the depth of the liquid is 0.045m up to the block's largest side. Find the density of the block?

Answer 1

$mg=F_A$

$\rho Vg=\rho_l V_l g$

$\rho V= \rho_l V_l$

$\rho h S=\rho_l h_l S$

$\rho h=\rho_l h_l$

$\rho=\rho_l \frac{h_l}{h}=13546\cdot \frac{0.045}{0.1}=6096 ~\frac{kg}{m^3}$