Question #153566

How to find the equation of trajectory using conservation of energy theorem


1
Expert's answer
2021-01-04T14:40:07-0500

Ep+Ek=constE_p+Ek = const

Ep,Ekpotential and kinetic energy of the bodyE_p,E_k-\text{potential and kinetic energy of the body}

Ep=mghE_p = mgh

Ек=mV22Ек = \frac{mV^2}{2}

let Ek=0;Ep=mghmax;const=mghmax\text{let }E_k =0;E_p=mgh_{max};const= mgh_{max}

mgh+mV22=mghmaxmgh +\frac{mV^2}{2}=mgh_{max}

h=hmaxV22gh= h_{max}-\frac{V^2}{2g}

h(t)=hmaxV(t)22g;V(t)change in speed over timeh(t)= h_{max}-\frac{V(t)^2}{2g};V(t) -\text{change in speed over time}

Answer:h(t)=hmaxV2(t)2g;V(t)changein speed over timeh(t)=h_{max}-\frac{V^2(t)}{2g};V(t)-\text{changein speed over time}


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