Question #152218

Charge particle in constant magnetic field
A particle of mass m and charge q is entering a region of space with uniform magnetic field
B⃗ . The particle initial (entering) velocity ⃗v0
has both components parallel and
perpendicular to the magnetic field B⃗ .
a) Write the equation of motion (EOM) for the particle and its general solutions.
b) Use relevant octave script provided to solve and plot the position of the particle as a
function of time.
c) Describe the state of motion of the particle based on the plots in part b)

Expert's answer

Answer

a) equation of motion can be written by using lorentz force as

F=q(E+v×B)F=q(E+v\times B)

F=ma=mdx2dt2F=ma=m\frac{dx^2}{dt^2}

Using above both equation

md2xdt2=q(E+v×B)m\frac{d^2x}{dt^2}=q(E+v\times B)

By applying above conditions in question

Solution is found

x=A+CeqBmtx=A+C e^{\frac{qB}{m}t}


B) above solution

x=A+CeqBmtx=A+C e^{\frac{qB}{m}t}

Compare with y=mx+c

So this is straight line equation with intercept A.


c) the state of motion of the particle based on the plots is straight line.



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