Question #152218
Charge particle in constant magnetic field
A particle of mass m and charge q is entering a region of space with uniform magnetic field
B⃗ . The particle initial (entering) velocity ⃗v0
has both components parallel and
perpendicular to the magnetic field B⃗ .
a) Write the equation of motion (EOM) for the particle and its general solutions.
b) Use relevant octave script provided to solve and plot the position of the particle as a
function of time.
c) Describe the state of motion of the particle based on the plots in part b)
1
Expert's answer
2020-12-23T07:45:50-0500

Answer

a) equation of motion can be written by using lorentz force as

F=q(E+v×B)F=q(E+v\times B)

F=ma=mdx2dt2F=ma=m\frac{dx^2}{dt^2}

Using above both equation

md2xdt2=q(E+v×B)m\frac{d^2x}{dt^2}=q(E+v\times B)

By applying above conditions in question

Solution is found

x=A+CeqBmtx=A+C e^{\frac{qB}{m}t}


B) above solution

x=A+CeqBmtx=A+C e^{\frac{qB}{m}t}

Compare with y=mx+c

So this is straight line equation with intercept A.


c) the state of motion of the particle based on the plots is straight line.



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