Question

This block is pushed by a spring attached to the wall, slides across the table, and then falls to the ground. The block has a mass m 1.35 kg. The spring constant is k = 560 N/m, and the spring has been compressed by 0.11 m. The block slides a distance d 0.65 m across the table of height h 0.75 m, find the speed of the block when it lands on the floor

Answer 1

Answer

Using energy conservation

Speed can be written as

$v=\sqrt{\frac{kx^2}{m}+2g(h-\mu d) }$

Putting all given value in above equation

$v=\sqrt{\frac{560\times(0.11)^2}{1.35}+2\times9.8(0.75-0.16\times0.65) }$ So speed

v=4.2m/s