The time it takes for a friend to reach the door:
tf=VfSf=540=8s
The time it takes you to reach the door:
t=δ+ta+tv
where δ=1s Time difference between you and your friend start to move
ta Time of uniformly accelerated motion
V=V0+ata; V0=0; ta=aV=27=3.5s
Sa=V0ta+2ata2=22∗3.52=12.25m
tv Running time at constant speed
tv=VS−Sa=730−12.25≈2.54s
t=δ+ta+tv=1+3.5+2.54=7.04
t<tf
Answer: You run the distance to the door before your friend
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