Question #137050

what is -5.00A + 4.00B

Expert's answer

For this question angle and co-ordinate points must be given for A and B.

Let the co-ordinate of A is(x1,y1)(x_1, y_1) and angle with positive x axis is=θ= \theta

And co-ordinate for the point B is (x2,y2)(x_2,y_2) and it is making an angle ϕ\phi

So, A=x1cos⁡θi^+y1sin⁡θj^A=x_1 \cos\theta \hat{i}+y_1\sin\theta\hat{j}

Similarly, B=x2cos⁡ϕi^+y2sin⁡ϕj^B=x_2\cos\phi\hat{i}+y_2\sin\phi\hat{j}

Now it is given C=−5.00A+4.00BC=-5.00A+4.00B

Now, substituting the values,

⇒C=−5(x1cos⁡θi^+y1sin⁡θj^)+4.00(x2cos⁡ϕi^+y2sin⁡ϕj^)\Rightarrow C=-5(x_1 \cos\theta \hat{i}+y_1\sin\theta\hat{j})+4.00(x_2\cos\phi\hat{i}+y_2\sin\phi\hat{j})

⇒C=(4x2cos⁡ϕ−5x1cos⁡θ)i^+(4y2sin⁡ϕ−5y1sin⁡θ)j^)\Rightarrow C=(4x_2\cos\phi-5x_1 \cos\theta)\hat{i}+(4y_2\sin\phi-5y_1\sin\theta)\hat{j})


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