Question #137050

what is -5.00A + 4.00B

1
Expert's answer
2020-10-07T10:11:43-0400

For this question angle and co-ordinate points must be given for A and B.

Let the co-ordinate of A is(x1,y1)(x_1, y_1) and angle with positive x axis is=θ= \theta

And co-ordinate for the point B is (x2,y2)(x_2,y_2) and it is making an angle ϕ\phi

So, A=x1cosθi^+y1sinθj^A=x_1 \cos\theta \hat{i}+y_1\sin\theta\hat{j}

Similarly, B=x2cosϕi^+y2sinϕj^B=x_2\cos\phi\hat{i}+y_2\sin\phi\hat{j}

Now it is given C=5.00A+4.00BC=-5.00A+4.00B

Now, substituting the values,

C=5(x1cosθi^+y1sinθj^)+4.00(x2cosϕi^+y2sinϕj^)\Rightarrow C=-5(x_1 \cos\theta \hat{i}+y_1\sin\theta\hat{j})+4.00(x_2\cos\phi\hat{i}+y_2\sin\phi\hat{j})

C=(4x2cosϕ5x1cosθ)i^+(4y2sinϕ5y1sinθ)j^)\Rightarrow C=(4x_2\cos\phi-5x_1 \cos\theta)\hat{i}+(4y_2\sin\phi-5y_1\sin\theta)\hat{j})


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS