As per the question,
Weight of the block "(w)=10N"
"m=10\/9.80=1.02kg"
Stiffness of the spring "(K)=200N\/m"
Compression in the spring "(x)=10cm= 0.1m"
Coefficient of kinetic friction"(\\mu_k)=0.2"
let the acceleration of the block after the release is a,
So, "Kx-\\mu w=ma"
"\\Rightarrow 200\\times 0.1-0.2\\times 10=1.02\\times a"
"\\Rightarrow a=\\dfrac{18}{1.02}=17.64 m\/sec^2"
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