A 3.250 g bullet enters a wooden block with a velocity of 80.00 m/s. If it exits the block with a velocity of 20.00 m/s, find the percent of mechanical energy lost to thermal energy due to friction.
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Expert's answer
2020-04-23T12:42:53-0400
loss in mechanical energy = loss in kinetic energy ="\\frac12m(v_1^2-v_2^2)=\\frac12\\times3.25\\times10^{-3}(80^2-20^2)=9.75 J"
initial kinetic energy = "\\frac12mv_1^2=10.4J"
loss percent = "\\dfrac{9.75}{10.4}\\times 100=93.75\\%"
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