For an isolated system of N>>1 distinct particles at temperature "T\\to\\infty" both energy states for particles will be equally probable, so an infinitely large temperature will correspond to the system energy "E_S=N\\frac{E}{2}" [1]. If the system goes into a state with an inverted population of levels i.e. the number of particles at the upper energy level will be greater than at the lower one we can talk about a state with a negative temperature.
Using this result we can specify that the subsystem of "\\frac {N}{2}" particles have a negative temperature if "E_{halfN}>\\frac{N}{2}\\frac{E}{2}=NE\/4" . It should be pointed out that a subsystem B (or A) consisting of N/2 particles cannot have an energy greater than "E_B=E\\cdot \\frac{N}{2}". At this energy all the particles are at the upper level of energy E. Thus it seems that an error has crept into the task condition and B has an energy "E_B=3 NE\/8>NE\/4" . Thus subsystem A has positive temperature, and subsystem B a negative one.
When the two subsystems are allowed to exchange energy we get the overall energy "E_S=E_A+E_B=NE\\frac{1}{8}+NE\\frac{3}{8}=N\\cdot\\frac{ E}{2}" and the system has a temperature formally corresponding to an infinite value "T\\to\\infty".
Answer: The range of energies "E_S" for which the system of N distinct particles has negative temperature is "NE>E_S>N\\frac{E}{2}" . The subsystem A has positive temperature, and system B a negative one. When the two subsystems are allowed to exchange energy the system will have a temperature formally corresponding to an infinite value.
[1] https://en.wikipedia.org/wiki/Negative_temperature
https://en.wikipedia.org/wiki/Negative_temperature#/media/File:Temperature_vs_E_two_state.svg
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