Question #111834
Consider an isolated system of N>>1distinct particles ,each of which can be in one of two states with energies 0 and E respectively.give the range of energies for which the system has negative temperature.The system is separated into two sub-systemsA and B,each having N/2 particles.Subsystem A has energy EA =NE/8 and B has energy EB=5 NE/8.Using the above result ,specify which of these subsystems has a positive temperature and negative temperature.The two subsystems are allowed to exchange energy.once equilibrium is attained,is the temperature of two systems positive or negative..?
1
Expert's answer
2020-04-28T09:47:26-0400

For an isolated system of N>>1 distinct particles at temperature TT\to\infty both energy states for particles will be equally probable, so an infinitely large temperature will correspond to the system energy ES=NE2E_S=N\frac{E}{2} [1]. If the system goes into a state with an inverted population of levels i.e. the number of particles at the upper energy level will be greater than at the lower one we can talk about a state with a negative temperature.

Using this result we can specify that the subsystem of N2\frac {N}{2} particles have a negative temperature if EhalfN>N2E2=NE/4E_{halfN}>\frac{N}{2}\frac{E}{2}=NE/4 . It should be pointed out that a subsystem B (or A) consisting of N/2 particles cannot have an energy greater than EB=EN2E_B=E\cdot \frac{N}{2}. At this energy all the particles are at the upper level of energy E. Thus it seems that an error has crept into the task condition and B has an energy EB=3NE/8>NE/4E_B=3 NE/8>NE/4 . Thus subsystem A has positive temperature, and subsystem B a negative one.

When the two subsystems are allowed to exchange energy we get the overall energy ES=EA+EB=NE18+NE38=NE2E_S=E_A+E_B=NE\frac{1}{8}+NE\frac{3}{8}=N\cdot\frac{ E}{2} and the system has a temperature formally corresponding to an infinite value TT\to\infty.


Answer: The range of energies ESE_S for which the system of N distinct particles has negative temperature is NE>ES>NE2NE>E_S>N\frac{E}{2} . The subsystem A has positive temperature, and system B a negative one. When the two subsystems are allowed to exchange energy the system will have a temperature formally corresponding to an infinite value.

[1] https://en.wikipedia.org/wiki/Negative_temperature

https://en.wikipedia.org/wiki/Negative_temperature#/media/File:Temperature_vs_E_two_state.svg


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