Question #293321

Derive the expression of the Q = ΔE of a nuclear reaction, hence, determine the Q value and the nature of the reaction F19 (H1,α) O16( 18.998405u, 15.994915u, 4.002603u, 1.007825u are masses of F19, O16, α, H1) respectively.



a ii). Discuss the primary processes by which gamma rays interact with matter



b). The Q value of the Na23 (n,α) F20 reaction is -5.4MeV. Determine the threshold energy of the neutrons for this reaction (22.9898u, 18.9964u, 4.0039u, 1.008665u are the masses of Na23, F20 α and n respectively).

Expert's answer

19F+1H→16O+4He,^{19}F+^1H\to ^{16}O+^4He,

Q=ΔE=(18.998405+1.007825−15.994915−4.002603)c2=4.7 MeV,Q=\Delta E=(18.998405+1.007825-15.994915-4.002603)c^2=4.7~MeV,


23Na+1n→20F+4He,^{23}Na+^1n\to^{20}F+^4He,

Q=ΔE=(22.9898+1.008665−19.9964−4.0039)c2=−5.3 MeV.Q=\Delta E=(22.9898+1.008665-19.9964-4.0039)c^2=-5.3~MeV.


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