find the fermi energy of copper by assuming that each copper atom contributes one free electron to the electron gas . the density of copper is 8.94 x 10^3kg/m^3
EF=h22m(3N8πV)23=6.97 eV.E_F=\frac{h^2}{2m}(\frac{3N}{8\pi V})^{\frac 23}=6.97~eV.EF=2mh2(8πV3N)32=6.97 eV.
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