Question #289883

A stone thrown from the top of a building is given an initial velocity of 20.0 m/s straight upward. The stone is launched 50.0 m above the ground Determine the time at which the stone reaches its maximum height.

1
Expert's answer
2022-01-23T16:14:04-0500

Given:

v0=20.0m/sv_0=20.0\:\rm m/s

g=9.81m/s2g=9.81\:\rm m/s^2

t?t-?


At the highest point the stone is at rest, hence

v=v0gt=0v=v_0-gt=0

The time of motion

t=v0/g=20.0/9.81=2.04st=v_0/g=20.0/9.81=2.04\:\rm s


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