A current of 2 A flowing through a coil of 100 turns gives rise to a magnetic flux of 5 × 10−5 Wb per turn. Calculate the magnetic energy associated with the coil
W=nΦI2=100⋅5⋅10−5⋅22=5 mJ.W=\frac{n\Phi I}2=\frac{100\cdot 5\cdot 10^{-5}\cdot 2}2=5~mJ.W=2nΦI=2100⋅5⋅10−5⋅2=5 mJ.
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