An unstable isotope with mass number210 emits 5.3MeV alpha particle. If the atomic mass of unstable isotope is 209.98 u and alpha particle is 4.0026u, determine the atomic mass of daughter nuclide.
84210Po→24He+82206Pb,_{84}^{210}Po\to _2^4He+_{82}^{206}Pb,84210Po→24He+82206Pb,
E=(mPo−mHe−mPb)c2,E=(m_{Po}-m_{He}-m_{Pb})c^2,E=(mPo−mHe−mPb)c2,
mPb=mPo−mHe−Ec2=205.9745 u.m_{Pb}=m_{Po}-m_{He}-\frac E{c^2}=205.9745~u.mPb=mPo−mHe−c2E=205.9745 u.
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