Question #157579

Find the power dissipated in:

(i) an extension cord having a 0.06 Ω resistance, through which 5.00 A is flowing.

(ii) a cord utilizing thinner wire, with a resistance of 0.300 Ω.


1
Expert's answer
2021-01-22T11:26:44-0500

Power is the rate of flow of energy. The power can be calculated from the formula

P=I2RP = I^2R

I = the amount of current flowing

R = the resistance through which current flowing

(i)

P=(5.00)2(0.06)=1.50  WP = (5.00)^2(0.06) \\ = 1.50 \;W

(ii)

P=(5.00)2(0.300)=7.50  WP = (5.00)^2(0.300) \\ = 7.50 \;W


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