Answer to Question #157579 in Atomic and Nuclear Physics for syeda sana

Question

Find the power dissipated in:

(i) an extension cord having a 0.06 Ω resistance, through which 5.00 A is flowing.

(ii) a cord utilizing thinner wire, with a resistance of 0.300 Ω.

Answer 1

Power is the rate of flow of energy. The power can be calculated from the formula

$P = I^2R$

I = the amount of current flowing

R = the resistance through which current flowing

(i)

$P = (5.00)^2(0.06) \\ = 1.50 \;W$

(ii)

$P = (5.00)^2(0.300) \\ = 7.50 \;W$