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Find the value of following 1. 4cot45O – sec60O +sin30O
Solve for each triangle. Round answers to nearest tenth. Triangle PQR angle P= 39, r=31 and p= 29
Solve each triangle. Round answer to nearest tenth. Triangle RPQ angle P=18 degrees angle Q= 122 degrees r=25
Jack and Jill ran up a hill to fetch a pail of water. They ran 100m to get to the top of a 30m tall hill. What is the degree of incline of the hill?
In △ ABC, ∠C = 30o


, c = 8.2cm, and b = 12.2cm.


Draw the triangle(s) and show 2 cases if there are two.
Maria says that sin A= disagree 12/18, cos A= 9/18, and tan A= 12/9. Do you agree or disagree? If you agree, explain why. If you disagree, explain what she did incorrectly and provide the correct solution.
In a circle of radius 30 inches, a central angle of 35 will intersect the circle forming an arc of length _____.
Let w be a negative real number, z a 6th root of w.


a) Show that z(k) = p^1/6 [cos ( pi + 2 * k* pi / 6) + i sin ( pi + 12 * k * pi / 6)], k = v, 1,2,3,4,5 is a formula for the 6th roots of w.


b) Hence determine 6th roots of - 729.


c) Given z = cosA + i sin A and u + iv = (1+z) (1+ z^2). Prove that v = u tan(3A/2), u^2 + v^2 = 16 cos ^2(A/2) cos^2A
(De Moivres theorem) - Use Cos5A and sin4A as polynomials in sinA and CosA to evaluate:


1) sin pi/5

2) sin2*pi/5

3) cos pi/5.
Louise is painting around a window frame on the outside of her house. Her ladder is 3.5m long and she placed it 1 m from the house. What is the vertical distance that the ladder reaches up the house? Round to one decimal place. Use the Pythagorean theorem.
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