Solve the equation 8sin^2𝑥−7=2cos𝑥 for 0≤𝑥≤360°, giving your answers to 1 decimal place.
Explanations & Calculations
8sin2x−7=2cosx8(1−cos2x)−7=2cosx8cos2x+2cosx−1=0(4cosx−1)(2cosx+1)=0cosx=14: x=75.50 & 284.50orcosx=−12:x=120.00 & 240.00\qquad\qquad \begin{aligned} \small 8\sin^2x-7&=\small 2\cos x\\ \small 8(1-\cos^2x)-7&=\small 2\cos x\\ \small 8\cos^2x+2\cos x-1&=\small 0\\ \small (4\cos x-1)(2\cos x+1)&=\small 0\\ \small \cos x &= \small \frac{1}{4}\quad: \, x = 75.5^0\,\&\,284.5^0\\ \small or\\ \small \cos x&=\small -\frac{1}{2}\quad: x=120.0^0\,\&\,240.0^0 \end{aligned}8sin2x−78(1−cos2x)−78cos2x+2cosx−1(4cosx−1)(2cosx+1)cosxorcosx=2cosx=2cosx=0=0=41:x=75.50&284.50=−21:x=120.00&240.00
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