Find the quadrant in which π(π‘) lies if π ππ π‘ > 0 and ππ π π‘ < 0.
csc t = 1/sin t
sec t = 1/ cos t
From the above illustration;
sin t < 0 in the 3rd and 4th Quadrant
and cos t >0 in the 1st and 4th Quadrant.
Therefore,
When sec t > 0 βΆ cos t > 0
and when csc t <0 βΆ sin t < 0
π(π‘) lies in the quadrant on which the two relations overlap each other
hence,
π(π‘) is in the 4th Quadrant [Answer]
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