Question #304119

the legs of a right triangle measure 5 inches and 7 inches


Expert's answer

Hypotenuse is 52+72=74.\sqrt{5^2+7^2}=\sqrt{74}. If θθ is the angle between the 7-inch leg and the hypotenuse then


cos⁡θ=774≈0.8137,sin⁡θ=574≈0.5812\cos \theta=\dfrac{7}{\sqrt{74}}\approx0.8137, \sin\theta=\dfrac{5}{\sqrt{74}}\approx 0.5812
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