Question #164870

The terminal arm of an angle is standard position passes through π‘ƒ(βˆ’5,5).

a. Sketch a diagram of an angle in standard position.

b. Determine the length of the hypotenuse.

c. Determine the primary trigonometric ratios to three decimal places.


Expert's answer

(a) Diagram of the angle in Standard position






(b) Length of the hypotenuse (Hyp)


Hyp=(βˆ’5)2+(5)2=25+25=50Hyp=52Hyp = \sqrt{(-5)^2 + (5)^2}\\ \qquad = \sqrt{25 + 25}\\ \qquad = \sqrt{50}\\ Hyp = 5\sqrt{2}



(c) The primary trigonometric ratios are sin, cos and tan.

Since the terminal arm lies in 2nd quadrant, we have to take positive signs for sin, while others are negative.


opp = 5, adj = -5


(i) sin

sin⁑α=opphyp=552=12=11.4142sin⁑α=0.707\sin{\alpha} = \dfrac{opp}{hyp}=\dfrac{5}{5\sqrt{2}}=\dfrac{1}{\sqrt{2}}=\dfrac{1}{1.4142}\\ \bold{\sin{\alpha} = 0.707}



(ii) cos

cos⁑α=adjhyp=βˆ’552=βˆ’12=βˆ’11.4142cos⁑α=βˆ’0.707\cos{\alpha} = \dfrac{adj}{hyp}=\dfrac{-5}{5\sqrt{2}}=-\dfrac{1}{\sqrt{2}}=-\dfrac{1}{1.4142}\\ \bold{\cos{\alpha} = -0.707}


(iii) tan

tan⁑α=oppadj=5βˆ’5=βˆ’1\tan{\alpha} = \dfrac{opp}{adj}=\dfrac{5}{-5}=\bold{-1}


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