Question #164868

Solve for angleT△𝑅𝑆𝑇, given π‘Ÿ=1.2π‘˜π‘š, π‘ =2.4π‘˜π‘š, π‘‘=2.2π‘˜π‘š


1
Expert's answer
2021-02-24T06:09:07-0500

Ans:-

According to the question we solve for angle ∠t\angle t

So, cos∠tcos\angle t == r2+s2βˆ’T22sr\dfrac{r^2+ s^2 -T^2}{2sr}

β‡’1.22+2.42βˆ’2.222Γ—2.4Γ—1.2\Rightarrow \dfrac{1.2^2+2.4^2-2.2^2}{2\times2.4\times1.2}


β‡’\Rightarrow cos∠t=cos\angle t = 0.41

β‡’\Rightarrow ∠t\angle t == 1.148



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