Question #135956

A navigator on a ship sailing on a course of 330°at 16 knots (nautical miles per hour) observes a lighthouse, due north of the ship. Fifteen minutes later, the lighthouse is due east of the ship. How far is the lighthouse at that instant?


Expert's answer

After 15 minutes, the ship shall cover ;


Distance =TimeTime ×speed(knots)×speed(knots)


1560×16knots=4nm\frac{15}{60} ×16 knots =4nm


From the initial point and at the point the navigator saw the Lighthouse are corresponding hence the ship was sailing N30°WN30°W


To get the distance of the Lighthouse ;


Sin30°=opp4nmSin 30°=\frac{opp} {4nm}


Distance =4 ××0.5=2nm


=2nm

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