Question #135956

A navigator on a ship sailing on a course of 330°at 16 knots (nautical miles per hour) observes a lighthouse, due north of the ship. Fifteen minutes later, the lighthouse is due east of the ship. How far is the lighthouse at that instant?


1
Expert's answer
2020-10-01T09:58:19-0400

After 15 minutes, the ship shall cover ;


Distance =TimeTime ×speed(knots)×speed(knots)


1560×16knots=4nm\frac{15}{60} ×16 knots =4nm


From the initial point and at the point the navigator saw the Lighthouse are corresponding hence the ship was sailing N30°WN30°W


To get the distance of the Lighthouse ;


Sin30°=opp4nmSin 30°=\frac{opp} {4nm}


Distance =4 ××0.5=2nm


=2nm

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