Sketch of the above situation

Let the width of the soccer net AB be x meters
Here, we apply the cosine rule;
a2=b2+c2−2bccosA
In the case above; we will apply;
c2=a2+b2−2abcosC
=502+522−(2×50×52)cos7°
=2500+2704−5200cos7°
=5204−5161.24
=42.76
c=x=6.54
Therefore the width of the soccer net is 6.54 meters.