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Ten cartoons are taken at random from an automatic filling machine. The mean net weight of the 10 cartoons is 11.8 kg and standard deviation is 0.15 kg. Does the sample mean differ significantly from the intend weight of 12 kg. Use 5% level of significance.
PROBLEM B: In the national achievement test, a school had a total mean of 59 with a standard deviation of 7. If 40 students who took the test are selected at random, what is the probability that the mean of their scores fall between 59 and 60?
The Grade 11 students of Capiz National High School took a 100 item Statistics exam. The scores fit the normal distribution with a mean of 75 and a standard deviation of 10. What is the percentage of students that got a score of 80 to 85?
a random sample of size n 16 is drawn from a normally distributed population. the sample mean is 98 with known standard deviation of 5. Construct a 98% confidence interval for the population mean.
A population consists of the five measurements 2, 6, 8, 0, and 1.
1. What is the mean and the standard deviation of the population?
what is the illustration of greater than 1.1150
The value of serum sodium in healthy adults approximately follows a normal distribution with a mean of 141meq/l and standard deviation of 3meq/l
(a) What is the probability that a normal healthy adult will have a serum sodium value above 147meq/l ( 5 marks)
(b) What is the probability that a normal healthy adult will have a serum sodium value below 130 meq/l ( 5 marks)
(c) What is the probability that a normal healthy adult will have a serum sodium value between 132 and 150meq/l (5 marks)
Two cards are drawn at random from a set of 52 cards.What is the probability that the both cards are either kings or queens
'Bhartdarshan’ is an Internet-based travel agency wherein customers can see videos of the
cities they plan to visit. The number of hits daily is a normally distributed random variable
with a mean of 10,000 and a standard deviation of 2,400.
a. What is the probability of getting more than 12,000 hits?
Let X be a discrete random variable with the following PMF: pX(x) = 1/2 for x = 0 1/3 for x = 1 1/6 for x = 2 0 otherwise (i) Compute SX, the range of the random variable X. (ii) Calculate P(X ≤ 0.5). (iii) Calculate P(0.25 < X < 0.75). (iv) Calculate P(X = 0.2|X < 0.6).
