a random sample of size n 16 is drawn from a normally distributed population. the sample mean is 98 with known standard deviation of 5. Construct a 98% confidence interval for the population mean.
CI=μ±zσn=98±2.33516=98±2.91CI=\mu \plusmn z \frac{\sigma}{\sqrt{n}}=98 \plusmn 2.33\frac{5}{\sqrt{16}}=98 \plusmn 2.91CI=μ±znσ=98±2.33165=98±2.91
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