The Grade 11 students of Capiz National High School took a 100 item Statistics exam. The scores fit the normal distribution with a mean of 75 and a standard deviation of 10. What is the percentage of students that got a score of 80 to 85?
We have a normal distribution, "\\mu=75, \\sigma=10."
Let's convert it to the standard normal distribution,
"z=\\cfrac{x-\\mu}{\\sigma}."
"z_1=\\cfrac{80-75}{10}=0.5;\\\\\nz_2=\\cfrac{85-75}{10}=1;\\\\\nP(80<X<85)=P(0.5<Z<1)=\\\\\n=P(Z<1)-P(Z<0.5)=\\\\\n=0.8413-0.6915=\\\\\n=0.1498=14.98\\% \\\\\n\\text{ (from z-table).}"
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