Null hypothesis "H_0: p=0.64."
Alternative hypothesis "H_a: p\\ne 0.64."
Test statistic: "z=\\frac{0.52-0.64}{\\sqrt{\\frac{0.64(1-0.64)}{100}}}=-2.50."
P-value: "p=2P(Z<-2.50)=0.012."
Since the P-value is less than 0.1, reject the null hypothesis.
There is a sufficient evidence that the Consumer report result does not apply to
the Publix in Clemson, SC.
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