A shipment of 5 computers contains three that are slightly defective. A retailer receives three of these computers at random. List the elements of the sample space 5 using the letter D and N for defective and none defective computers respectively. To each sample point assign a value of X of the random variable X representing which is slightly defective.
Let X= the number of slightly defective computers
3N,0D
X=0
This combination does not exist, because 5−3=2<3. A retailer can receive at most 2 normal computers.
2N,1D
X=1
P(2N & 1D)=(35)(25−3)(13)=3!(5−3)!5!1⋅3=103 1N,2D
X=2
P(1N & 2D)=(35)(15−3)(23)=102⋅3=53 0N,3D
X=3
P(0N & 3D)=(35)(05−3)(33)=101⋅1=101 Sample space:
S={NND,NDN,NDD,DNN,DND,DDN,DDD}
SX={1,2,3}
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