Question #98436
A shipment of five computers contains three that are slightly defective. A retailer recieves three of these computers at random
1
Expert's answer
2019-11-12T09:54:54-0500

A shipment of 5 computers contains three that are slightly defective. A retailer receives three of these computers at random. List the elements of the sample space 5 using the letter D and N for defective and none defective computers respectively. To each sample point assign a value of X of the random variable X representing which is slightly defective.

Let X=X= the number of slightly defective computers

3N,0D3N, 0D

X=0X=0

This combination does not exist, because 53=2<3.5-3=2<3. A retailer can receive at most 2 normal computers.

2N,1D2N, 1D

X=1X=1


P(2N & 1D)=(532)(31)(53)=135!3!(53)!=310P(2N \ \&\ 1D)={\binom{5-3}{2}\binom{3}{1} \over \binom{5}{3}}={1\cdot3 \over {5! \over 3!(5-3)!}}={3 \over 10}

1N,2D1N, 2D

X=2X=2


P(1N & 2D)=(531)(32)(53)=2310=35P(1N \ \&\ 2D)={\binom{5-3}{1}\binom{3}{2} \over \binom{5}{3}}={2\cdot3 \over 10}={3 \over 5}

0N,3D0N, 3D

X=3X=3


P(0N & 3D)=(530)(33)(53)=1110=110P(0N \ \&\ 3D)={\binom{5-3}{0}\binom{3}{3} \over \binom{5}{3}}={1\cdot1 \over 10}={1 \over 10}

Sample space:


S={NND,NDN,NDD,DNN,DND,DDN,DDD}S=\{{NND, NDN,NDD,DNN, DND, DDN,DDD}\}

SX={1,2,3}S_X=\{{1,2,3}\}

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