Answer to Question #98445 in Statistics and Probability for C

Question #98445
The digits 1 to 7 are used to create a four digit code to enter a locked room.How many different process are possible if the digits may not be repeated and the code must be an even number bigger than 5000.?Please explain
1
Expert's answer
2019-11-13T12:06:51-0500

Answer: 160

Solution:

First digit can be: 5, 6, 7 (3 variants totally).

Second digit can be: any (7 variants totally).

Third digit can be: any (7 variants totally).

Fourth digit can be: 2,4,6 (3 variants totally).


If the first digit is 5, than there are 3 ways to choose the fourth digit, 5 ways to choose the third digit, 4 ways to choose the second digit.

If the first digit is 6, than there are 2 ways to choose the fourth digit, 5 ways to choose the third digit, 4 ways to choose the second digit.

If the first digit is 7, than there are 3 ways to choose the fourth digit, 5 ways to choose the third digit, 4 ways to choose the second digit.


Overall:

"Number=3\u00d75\u00d74\\,+\\,2\u00d75\u00d74\\,+\\,3\u00d75\u00d74=60+40+60=160"


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Comments

Assignment Expert
14.11.19, 15:59

Other cases can be explained in a similar way.

Assignment Expert
14.11.19, 15:59

The number is bigger than 5000. Let the first digit be 5, a fixed digit. Because the code must be even, then 3 choices are possible for the fourth digit because only 2, 4, 6 are even digits among digits 1 to 7. Because the digits cannot be repeated and two digits for the first and the fourth places have already been selected, then 7-2=5 choices are possible for the second digit. Finally, the third digit can be chosen in 5-1=4 ways because the digits cannot be repeated.

C
13.11.19, 19:20

Hi,thanks for the answer.Im not sure about the choices for the second,third and fourth digits?please explain to me

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