This problem can be modeled by Markov chain
Consider states :
4.employee joined no plan
Transition matrix A with elements aij = one step transitional probabilities from state i to state j
A:
Matrix A is transition matrix of absorbing Markov chain:
where I is 3x3 identity matrix, R is row matrix = (0.04, 0.14, 0.07), Q = 0.75,
Power n of transition matrix of absorbing Markov chain can be found by formula:
Where I - identity matrices of corresponding size.
In given case (I + Q + Q2 + ... +Qn) is geometric series and approaches to 1/(1-Q), when n -> infinity. Qn =0.75n -> 0.
Limit of An when n -> infinity is
"=\\begin{vmatrix}\n 1& 0&0&0\\\\ 0&1&0&0\\\\0&0&1&0\\\\0.16&0.56&0.28&0\n\\end{vmatrix}"
"(0, 0, 0, 1)*\\begin{vmatrix}\n 1& 0&0&0\\\\ 0&1&0&0\\\\0&0&1&0\\\\0.16&0.56&0.28&0\n\\end{vmatrix}=(0.16, 0.56, 0.28, 0)"
if at the beginning no employee joined any plan, then in the long run 16% will join plan A, 56% will join plan B and 28% will join plan C.
b)Time T to join a plan has geometric distribution with probability of success p = 0.25 (probability to join one of the plans in given year) .
Expectation E(T) = 1/p = 1/0.25 = 4.
Answer: a) 16% of employees will join plan A 56%of employees will join plan B, 28% of employees will join plan C
b)Expectation of time for employee to join one of the plans is 4 years.
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