All possible samples:{(2,5), (2,8), (5,8)}.
Sample means for these samples: 3.5, 5, 6.5.
Mean of the sample means: (3.5+5+6.5)/3=5.
Population mean: (2+5+8)/3=5.
So, the sample mean is an unbiased estimate of the population mean.
Population variance: "\\sigma^2=\\frac{(2-5)^2+(5-5)^2+(8-5)^2}{3}=6."
The variance of the sampling distribution of means: "\\sigma_x^2=\\frac{\\sigma^2(N-n)}{n(N-1)}=\\frac{6(3-2)}{2(3-1)}=\\frac{3}{2}"
The standard deviation of the sampling distribution of means: "\\sigma_x=\\sqrt{\\frac{3}{2}}"
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Dear Ric, please use the panel for submitting a new question.
4,5 and 6 n=2
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