"P(X=3)=\\frac{1}{3}P(X=4)\\\\\ne^{-\\lambda}\\frac{\\lambda^3}{3!}=\\frac{1}{3}e^{-\\lambda}\\frac{\\lambda^4}{4!}\\\\\n\\lambda=\\frac{3*4!}{3!}=12\\\\\nMean=Variance=\\lambda=12\\\\\nStandard\\; deviation=\\sqrt{12}=2\\sqrt{3}"
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