Question #72705

The average number of field mice per acre in
a 5-acre wheat field is estimated to be 12. Find the
probability that fewer than 7 field mice are found
(a) on a given acre;
(b) on 2 of the next 3 acres inspected

Expert's answer

Question #72705, Math / Statistics and Probability

The average number of field mice per acre in a 5-acre wheat field is estimated to be 12. Find the probability that fewer than 7 field mice are found

(a) on a given acre;

(b) on 2 of the next 3 acres inspected

Answer.

(a) Poisson distribution with a mean μ=12\mu = 12.


P(X<7)=e12(1200!+1211!+1222!+1233!+1244!+1255!+1266!)=0.0458.P(X < 7) = e^{-12} \left( \frac{12^0}{0!} + \frac{12^1}{1!} + \frac{12^2}{2!} + \frac{12^3}{3!} + \frac{12^4}{4!} + \frac{12^5}{5!} + \frac{12^6}{6!} \right) = 0.0458.


(b) Binomial distribution with p=0.0458p = 0.0458, n=3n = 3.


P(X=2)=C320.04582(10.0458)=0.0060.P(X = 2) = C_3^2 0.0458^2(1 - 0.0458) = 0.0060.


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