Answer on Question #72635 – Math – Statistics and Probability Question
Suppose that airplane engines operate independently and fail with probability equal to 0.4. Assuming that a plane makes a safe flight if at least one-half of its engines run, determine whether a 4-engine plane or a 2-engine plane has the higher probability for a successful flight.
Solution
Let X be the random variable representing the number of engines running out of n engines in a plane. Let us consider, running of an engine is a success.
Then q=0.4,p=1−q=1−0.4=0.6.
Trials are independent.
Hence, X∼Bin(n,p=0.6)
The probability mass function (p.m.f) is
P(X=x)=b(x;n,0.6), where x=0,1,2,…,nP(X=x)=(xn)(0.6)x(0.4)n−x, where x=0,1,2,…,n
a) For the 2-engine plane to make a successful flight, at least one engine must be running.
If n=2,X∼Bin(2,p=0.6).
Then
P(at least one−half of its engines run)=P(X≥1)=1−P(X=0)==1−(02)(0.6)0(0.4)2−0=1−(0.4)2=0.84
b) On the other hand, for the 4-engine plane to make a successful flight, at least two engines must be running.
If n=4,X∼Bin(4,p=0.6).
Then
P(at least one−half of its engines run)=P(X≥2)=1−P(X<2)==1−(P(X=0)+P(X=1))==1−((04)(0.6)0(0.4)4−0+(14)(0.6)1(0.4)4−1)==1−((0.4)4+4(0.6)(0.4)3)=0.8208
Since 0.84>0.8208, the 2-engine plane has a higher probability for a successful flight than the 4-engine plane.
**Answer**: the 2-engine plane has a higher probability for a successful flight than the 4-engine plane.
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