Prove that the probability of P(A/B)=0
Solution:
"P(A\/B)-" called condition probability;
If A and B are two events in a sample space S, then the conditional probability of A
A given B is defined as:
"P(A\/B)=\\frac{P(A\u2229B)}{P(B)};" when "P(B)\\ne0;"
When A and B are disjoint they can not both occur at the same time. Thus, given that B has occurred, the probability of A must be zero. "A\u2229B=\u2205; \\space P(A\u2229B)=0." Because, when B occurred, A can not occurred.
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