Question #346741

A question in Probability & Statics:-


At a checkout counter, customers arrive at an average of 1.5

per minute. Assuming poisson distribution

1- The probability of no arrival in two minutes is.....

2- The variance of the number of arrivals in two minutes

is.....

3- Suppose X has binomial distribution with n=1000 and p

=0.002 , Then P(x=3)=....


1
Expert's answer
2022-06-02T14:53:22-0400

1. XPo(λt),λt=1.5(2)=3X\sim Po(\lambda t), \lambda t=1.5(2)=3


P(X=0)=e3(3)00!=0.049787P(X=0)=\dfrac{e^{-3}(3)^0}{0!}=0.049787

2.


Var(X)=λt=3Var(X)=\lambda t=3

3. When the value of nn  in a binomial distribution is large and the value of pp is very small, the binomial distribution can be approximated by a Poisson distribution. If n>20n > 20 and np<5np < 5 or nq<5nq < 5 then the Poisson is a good approximation.

Check


n=1000>20,np=1000(0.002)=2<10n=1000>20, np=1000(0.002)=2<10


Then λ=np=2\lambda=np=2

XPo(2)X\sim Po(2)

P(X=3)=e2(2)33!P(X=3)=\dfrac{e^{-2}(2)^3}{3!}=0.180447=0.180447




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