A question in Probability & Statics:-
At a checkout counter, customers arrive at an average of 1.5
per minute. Assuming poisson distribution
1- The probability of no arrival in two minutes is.....
2- The variance of the number of arrivals in two minutes
is.....
3- Suppose X has binomial distribution with n=1000 and p
=0.002 , Then P(x=3)=....
1. "X\\sim Po(\\lambda t), \\lambda t=1.5(2)=3"
2.
3. When the value of "n" in a binomial distribution is large and the value of "p" is very small, the binomial distribution can be approximated by a Poisson distribution. If "n > 20" and "np < 5" or "nq < 5" then the Poisson is a good approximation.
Check
Then "\\lambda=np=2"
"X\\sim Po(2)"
"P(X=3)=\\dfrac{e^{-2}(2)^3}{3!}""=0.180447"
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