Question #346738

A secretary makes 2 errors per page on the average. What is the probability that on the next 

page she makes; 4 or more errors and no error?


1
Expert's answer
2022-06-01T13:10:43-0400

Average error per page λ=2\lambda=2

Let X denote the number of Errors: XPo(λ)X\sim Po(\lambda)


(a) 

P(X4)=1P(X=0)P(X=1)P(X\ge4)=1-P(X=0)-P(X=1)




P(X=2)P(X=3)-P(X=2)-P(X=3)

=1e2(2)00!e2(2)11!e2(2)22!=1-\dfrac{e^{-2}(2)^0}{0!}-\dfrac{e^{-2}(2)^1}{1!}-\dfrac{e^{-2}(2)^2}{2!}

e2(2)33!=0.14287-\dfrac{e^{-2}(2)^3}{3!}=0.14287


(b) 

P(X=0)=e2(2)00!=0.13534P(X=0)=\dfrac{e^{-2}(2)^0}{0!}=0.13534




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