The office for admission of XYZ University found out that the IQ of incoming 1200 freshmen normally distributed with a mean of 108 and a standard deviation of 10.
P(90<X<120)=P(X<120)−P(X≤90)
=P(Z<10120−108)−P(Z≤1090−108)
=P(Z<1.2)−P(Z≤−1.8)
≈0.88493−0.03593=0.8490

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