We assume that variables are continuous. We remind that for random variables X1, X2, X3 we have: P(X1≤x1,X2≤x2,X3≤x3)=∫0x1∫0x2∫0x3f(x1,x2,x3)dx1dx2dx3, where 0<x1<1,0<x2<1,0<x3<1.
(i) The value c can be determined from the following equality: 1=∫01∫01∫01f(x1,x2,x3)dx1dx2dx3. We receive: 1=∫01∫01∫01c(x1+2x2+3x3)dx1dx2dx3=c∫01∫01(21x12+2x2x1+3x3x1)∣01dx2dx3=c∫01∫01(21+2x2+3x3)dx2dx3=c∫01(21x2+x22+3x3x2)∣01dx3=c∫01(23+3x3)dx3=c(23x3+23x32)∣01=3c
From the latter we receive that c=31.
(ii) The joint marginal density function can be received in the following way: f(x1,x2)=31∫01(x1+2x2+3x3)dx3=31(x1x3+2x2x3+23x32)∣01=31(x1+2x2+23).
Thus, we receive that f(x1,x2)=31(x1+2x2+23).
Answer: (i) c=31; (ii) f(x1,x2)=31(x1+2x2+23).
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