Question #336362

A Jar contains 24 red marbles numbered 1 to 24 and 50 blue marbles numbered 1 to 50. A marble is drawn at random from the Jar. Find the probability of the given event. Please enter reduced fractions.


a) The marble is red. P(red)=

b) The marble is odd numbered. P(odd)=

c) The marble is red or odd numbered. P(red or odd)=

d)The marble is blue or even numbered. P(blue or even)=


1
Expert's answer
2022-05-02T16:16:15-0400

a)

P(Red)=2424+50=1237P(Red)=\dfrac{24}{24+50}=\dfrac{12}{37}

b)

P(Odd)=12+2524+50=12P(Odd)=\dfrac{12+25}{24+50}=\dfrac{1}{2}

c)


P(RedOdd)=24+2524+50=4974P(Red\cup Odd)=\dfrac{24+25}{24+50}=\dfrac{49}{74}

d)


P(BlueEven)=12+5024+50=3137P(Blue\cup Even)=\dfrac{12+50}{24+50}=\dfrac{31}{37}


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