Question #336235



A. The following are the heights of four students in centimeters. Suppose


samples of size 2 are taken from this population of four students.


STUDENTS | HEIGHT(in cm)



Cardo 125



Alyana 120



Joaquin 130



Flora 110



a. Compute the mean of the population


b. Compute the mean of the sampling distribution of the sample means

Expert's answer

We have population values 125, 120, 130, 110, population size N=4 and sample size n=2.

Mean of population (μ)(\mu) = 

125+120+130+1104=121.25\dfrac{125+120+130+110}{4}=121.25


The number of possible samples which can be drawn without replacement is NCn=4C2=6.^{N}C_n=^{4}C_2=6.

noSampleSamplemean (xˉ)1125,120245/22125,130255/23125,110235/24120,130250/25120,110230/26130,110240/2\def\arraystretch{1.5} \begin{array}{c:c:c:c:c} no & Sample & Sample \\ & & mean\ (\bar{x}) \\ \hline 1 & 125,120 & 245/2 \\ \hdashline 2 & 125, 130 & 255/2 \\ \hdashline 3 & 125,110 & 235/2 \\ \hdashline 4 & 120,130 & 250/2 \\ \hdashline 5 & 120,110 & 230/2 \\ \hdashline 6 & 130,110 & 240/2 \\ \hdashline \end{array}




Xˉf(Xˉ)Xˉf(Xˉ)230/21/6230/12235/21/6235/12240/21/6240/12245/21/6245/12250/21/6250/12255/21/6255/12\def\arraystretch{1.5} \begin{array}{c:c:c:c} \bar{X} & f(\bar{X}) &\bar{X} f(\bar{X}) \\ \hline 230/2 & 1/6 & 230/12\\ \hdashline 235/2 & 1/6 & 235/12\\ \hdashline 240/2 & 1/6 & 240/12\\ \hdashline 245/2 & 1/6 & 245/12 \\ \hdashline 250/2 & 1/6 & 250/12\\ \hdashline 255/2 & 1/6 & 255/12 \\ \hdashline \end{array}


Mean of sampling distribution 

μXˉ=E(Xˉ)=Xˉif(Xˉi)=121.25=μ\mu_{\bar{X}}=E(\bar{X})=\sum\bar{X}_if(\bar{X}_i)=121.25=\mu




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