We have population values 125, 120, 130, 110, population size N=4 and sample size n=2.
Mean of population (μ) =
4125+120+130+110=121.25
The number of possible samples which can be drawn without replacement is NCn=4C2=6.
no123456Sample125,120125,130125,110120,130120,110130,110Samplemean (xˉ)245/2255/2235/2250/2230/2240/2
Xˉ230/2235/2240/2245/2250/2255/2f(Xˉ)1/61/61/61/61/61/6Xˉf(Xˉ)230/12235/12240/12245/12250/12255/12
Mean of sampling distribution
μXˉ=E(Xˉ)=∑Xˉif(Xˉi)=121.25=μ
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