Question #336215

It has been reported that 40% of the adult population participate in computer hobbies during their leisure time. A random sample of 180 adults found that 65 engaged in computer hobbies. at a= 0.01, is there sufficient evidence to conclude that the proportion differs from 40%?



1
Expert's answer
2022-05-02T15:55:19-0400

The following null and alternative hypotheses for the population proportion needs to be tested:

H0:p=0.4H_0:p=0.4

Ha:p0.4H_a:p\not=0.4

This corresponds to a two-tailed test, for which a z-test for one population proportion will be used.

The z-statistic is computed as follows:


z=p^p0p0(1p0)n=651800.40.4(10.4)1801.0650z=\dfrac{\hat{p}-p_0}{\sqrt{\dfrac{p_0(1-p_0)}{n}}}=\dfrac{\dfrac{65}{180}-0.4}{\sqrt{\dfrac{0.4(1-0.4)}{180}}}\approx-1.0650

The p-value is p=2P(Z<1.0650)=2(0.143438)p =2P(Z<-1.0650)= 2(0.143438)

=0.286876.=0.286876.

Based on the information provided, the significance level is α=0.01,\alpha = 0.01, and the critical value for a two-tailed test is zc=2.5758.z_c = 2.5758.

The rejection region for this two-tailed test is R={z:z>2.5758}.R = \{z: |z|>2.5758\}.

Since it is observed that z=1.0650<2.5758=zc,|z| = 1.0650 <2.5758= z_c , it is then concluded that the null hypothesis is not rejected.

Using the P-value approach: The p-value is p=0.286876,p =0.286876, and since p=0.2868760.01=α,p = 0.286876 \ge 0.01=\alpha, it is concluded that the null hypothesis is not rejected.

Therefore, there is not enough evidence to claim that the population proportion pp is different than 0.40, at the α=0.01\alpha = 0.01 significance level.



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