Question #333687

The number of road construction projects that take place at any one time in a certain city follows a Poisson distribution with a mean of 7. Find the probability that more than four road construction projects are currently taking place in the city


1
Expert's answer
2022-04-26T14:08:37-0400

Let X=X= the number of road construction projects: XPo(λ).X\sim Po(\lambda).  

Given λ=7.\lambda=7.


P(X>4)=1P(X4)P(X>4)=1-P(X\le 4)

=1P(X=0)P(X=1)=1-P(X=0)-P(X=1)

P(X=2)P(X=3)P(X=4)-P(X=2)-P(X=3)-P(X=4)

=1eλλ00!eλλ11!=1-\dfrac{e^{-\lambda}\cdot\lambda^0}{0!}-\dfrac{e^{-\lambda}\cdot \lambda^1}{1!}

eλλ22!eλλ33!eλλ44!-\dfrac{e^{-\lambda}\cdot\lambda^2}{2!}-\dfrac{e^{-\lambda}\cdot \lambda^3}{3!}-\dfrac{e^{-\lambda}\cdot \lambda^4}{4!}

=1e7(1+7+49/2+343/6+2401/24)=1-e^ {-7}(1+7+49/2+343/6+2401/24)

0.82701\approx 0.82701


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