Question

Hammer It Out is a panel beater business in Silverton, Pretoria, that repairs cars that have been involved in accidents. It finds that it receives cars for repair at a rate of 3 per day.

Calculate the probability of Hammer It Out receiving 20 cars for repair during a random week (they operate 5 days a week).

Answer 1

This is Poisson distribution

$\lambda=3\times5=15$

k=20

$P(k)=\frac{\lambda^k e^{-\lambda}}{k!}=\frac{15^{20}e^{-15}}{20!}=0.0418$