Question #333520

The weight of 1000 children average 50 kg and the standard deviation is 5kg. What is the Area under the normal curve that corresponds to the z-score of 55


kg?

1
Expert's answer
2022-04-26T13:16:29-0400

Let XX be a random variable denotes the children's weight: XN(μ,σ2)X\sim N(\mu, \sigma^2)


Z=XμσN(0,1)Z=\dfrac{X-\mu}{\sigma}\sim N(0, 1)

z=55z=55


P(Z=55)=0P(Z=55)=0

P(Z<55)=P(Z55)1P(Z<55)=P(Z\le 55)\approx1

P(Z>55)=P(Z55)0P(Z>55)=P(Z\ge 55)\approx0


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