Suppose the mean amount of cholesterol in eggs labeled “large” is 186 milligrams, with standard deviation 7 milligrams. Find the probability that the mean amount of cholesterol in a sample of 144 eggs will be within 1.5 milligrams of the population mean.
We have a normal distribution, "\\mu=186, \\sigma=7,n=144."
Let's convert it to the standard normal distribution,
"z=\\cfrac{\\bar{x}-\\mu}{\\sigma\/\\sqrt{n}}."
"\\bar{x}_1=186-1.5=184.5;\\\\\\bar{x}_2=186+1.5=187.5;\\\\\nz_1=\\cfrac{184.5-186}{7\/\\sqrt{144}}=-2.57;\\\\\nz_2=\\cfrac{187.5-186}{7\/\\sqrt{144}}=2.57;\\\\\nP(184.5<\\bar{X}<187.5)=P(-2.57<Z<2.57)=\\\\\n=P(Z<2.57)-P(Z<-2.57)=\\\\\n=0.9949-0.0051=0.9898 \\text{ (from z-table).}"
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