Answer to Question #326980 in Statistics and Probability for jsjaja

Question #326980

A sample of 60 Grade 9 students' ages was obtained to estimate the mean age of all Grade 9 students.



X = 15.3 years and the population variance is 16.



a. What is the point estimate for u.?



b. Find the 95% confidence interval for u?



c. Find the 99% confidence interval for u?

1
Expert's answer
2022-04-14T04:40:03-0400

a:μ^=xˉ=15.3b:(xˉσnz1+γ2,xˉ+σnz1+γ2)=(15.34601.960,15.3+4601.960)==(14.2879,16.3121)c:(xˉσnz1+γ2,xˉ+σnz1+γ2)=(15.34602.576,15.3+4602.576)==(13.9698,16.6302)a:\\\hat{\mu}=\bar{x}=15.3\\b:\\\left( \bar{x}-\frac{\sigma}{\sqrt{n}}z_{\frac{1+\gamma}{2}},\bar{x}+\frac{\sigma}{\sqrt{n}}z_{\frac{1+\gamma}{2}} \right) =\left( 15.3-\frac{4}{\sqrt{60}}\cdot 1.960,15.3+\frac{4}{\sqrt{60}}\cdot 1.960 \right) =\\=\left( 14.2879,16.3121 \right) \\c:\\\left( \bar{x}-\frac{\sigma}{\sqrt{n}}z_{\frac{1+\gamma}{2}},\bar{x}+\frac{\sigma}{\sqrt{n}}z_{\frac{1+\gamma}{2}} \right) =\left( 15.3-\frac{4}{\sqrt{60}}\cdot 2.576,15.3+\frac{4}{\sqrt{60}}\cdot 2.576 \right) =\\=\left( 13.9698,16.6302 \right)


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