Consider all samples of size 5 from this population: 2 5 6 8 10 12 13
a) Compute the mean (μ) and standard deviation (σ) of the population.
b) Calculate the mean and the standard deviation of the sampling distribution of the sample means.
a:μ=2+5+6+8+10+12+137=8σ=(2−8)2+(5−8)2+(6−8)2+(8−8)2+(10−8)2+(12−8)2+(13−8)27=3.6645b:μxˉ=μ=8.5σxˉ=σn=3.66455=1.63881a:\\\mu =\frac{2+5+6+8+10+12+13}{7}=8\\\sigma =\sqrt{\frac{\left( 2-8 \right) ^2+\left( 5-8 \right) ^2+\left( 6-8 \right) ^2+\left( 8-8 \right) ^2+\left( 10-8 \right) ^2+\left( 12-8 \right) ^2+\left( 13-8 \right) ^2}{7}}=3.6645\\b:\\\mu _{\bar{x}}=\mu =8.5\\\sigma _{\bar{x}}=\frac{\sigma}{\sqrt{n}}=\frac{3.6645}{\sqrt{5}}=1.63881a:μ=72+5+6+8+10+12+13=8σ=7(2−8)2+(5−8)2+(6−8)2+(8−8)2+(10−8)2+(12−8)2+(13−8)2=3.6645b:μxˉ=μ=8.5σxˉ=nσ=53.6645=1.63881
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