Two students are to be selected at random from a class with 10 girls and 12 boys. What is the probability that both will be girls, if selected
a) With replacement
b) Without replacement
a) For the first choice the total number of outcomes is 10 + 12 = 22, the number of favorable outcomes is 10; for the second choice the numbers are the same, since the choice of students is with a replacement.
"P_1=\\cfrac{10}{22}\\cdot\\cfrac{10}{22}=\\cfrac{100}{484}=\\cfrac{25}{121}=0.2066."
b) For the first choice the total number of outcomes is 10 + 12 = 22, the number of favorable outcomes is 10; for the second choice the total number of outcomes is 9 + 12 = 21, the number of favorable outcomes is 9,
"P_2=\\cfrac{10}{22}\\cdot\\cfrac{9}{21}=\\cfrac{90}{462}=\\cfrac{15}{77}=0.1948."
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